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-4.9t^2+15.8t+75=0
a = -4.9; b = 15.8; c = +75;
Δ = b2-4ac
Δ = 15.82-4·(-4.9)·75
Δ = 1719.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15.8)-\sqrt{1719.64}}{2*-4.9}=\frac{-15.8-\sqrt{1719.64}}{-9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15.8)+\sqrt{1719.64}}{2*-4.9}=\frac{-15.8+\sqrt{1719.64}}{-9.8} $
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